Answer:
Solution : (15, - 11)
Explanation:
We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )
![\begin{bmatrix}-4&-5&|&-5\\ -6&-8&|&-2\end{bmatrix}](https://img.qammunity.org/2021/formulas/mathematics/high-school/czx7s1htyhyttcfiyl46n4tw4fhjepthfx.png)
Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )
Row Echelon Form :
![\begin{pmatrix}1\:&\:\cdots \:&\:b\:\\ 0\:&\ddots \:&\:\vdots \\ 0\:&\:0\:&\:1\end{pmatrix}](https://img.qammunity.org/2021/formulas/mathematics/high-school/6j2tfg484hc3dc2qhzwjopuay1dbrfrl43.png)
Step # 1 : Swap the first and second matrix rows,
![\begin{pmatrix}-6&-8&-2\\ -4&-5&-5\end{pmatrix}](https://img.qammunity.org/2021/formulas/mathematics/high-school/iezxh7oxk1y7bgbdg37l98un93hh1e4rjb.png)
Step # 2 : Cancel leading coefficient in row 2 through
,
![\begin{pmatrix}-6&-8&-2\\ 0&(1)/(3)&-(11)/(3)\end{pmatrix}](https://img.qammunity.org/2021/formulas/mathematics/high-school/1su78he9de8mzq9czjefafwn0i1dazdykx.png)
Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.
![\begin{bmatrix}1&0&|&15\\ 0&1&|&-11\end{bmatrix}](https://img.qammunity.org/2021/formulas/mathematics/high-school/j7c7224a6r6l0cpgkpx3i5p2p2iu1v18ua.png)
As you can see our solution is x = 15, y = - 11 or (15, - 11).