Question

Quadratic and Ratios...​

Answer 1

x=0

Explanation:

in the quadratic formula to only have one solution

`b^(2) -4ac=0` for
`ax^2+bx+c=0`

so we have

`ax^2+b=c`

`ax^2+(b-c)=0`

if we insert in the formula we have

`0^2-4(a)(b-c)=0\\\\-4ab+4ac=0\\\\4ac=4ab\\\\(4ac)/(4a) = (4ab)/(4a)\\\\c=b`

`ax^2+b=c\\\\ax^2=b-b\\\\ax^2=0` since a≠0

`(ax^2)/(a)=(0)/(a) \\\\x^2=0\\\\x=0`