Question

When the hydraulic conductivity Ks = 10 mm/hr; effective matrix potential Ns = 20 mm, and rainfall intensity I = 30 mm/hr , determine the amount of runoff generated when the runoff rate reaches 15 mm/hr?( 2.7 mm or 0.21 mm or 18 mm or 0.67 mm)

Answer 1

`t = 0.75 \ hr = 0.75 *60 = 45 \ minutes`

Step-by-step explanation:

From the question we are told that

The hydraulic conductivity is
`Ks = 10\ mm/hr`

The effective matrix potential
`Ns = 20 \ mm`

The intensity of rainfall is
`I = 30 \ mm/hr`

The runoff rate
`R = 15 \ mm/hr`

Generally the run off rate is mathematically represented as

`R = (I - Ks) t`

Here t is the amount of runoff generated

=>
`15 = (30 - 10) t`

=>
`t = 0.75 \ hr`

converting to minutes

`t = 0.75 \ hr = 0.75 *60 = 45 \ minutes`