Question

A child goes down a slide, starting from rest. If the length of the slide is 2 m and it takes the child 3 seconds to go down the slide, what is the child's acceleration?

Answer 1

0.44 m/s^2

Step-by-step explanation:

initial velocity = 0 (since the child starts from rest)

distance covered by the child = 2 m (the length of the slide)

time taken = 3 sec

acceleration of the child = ?

using Newton's equation of motion

s =
`ut + (1)/(2)at^(2)`

where s is the distance covered by the child

u is the initial velocity

a is the acceleration

t is the time spent

substituting values, we have

2 = 0(3) +
`(1)/(2)a*3^(2)`

2 = 9a/2

4 = 9a

a = 4/9 = 0.44 m/s^2