Question

Please solve, -37-2v= -6(2v-3)-5​

Answer 1

`\huge\boxed{v=5}`

Explanation:

`-37-2v=-6(2v-3)-5\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\-37-2v=(-6)(2v)+(-6)(-3)-5\\\\-37-2v=-12v+18-5\\\\-37-2v=-12v+(18-5)\\\\-37-2v=-12v+13\qquad\text{add 37 to both sides}\\\\-37+37-2v=-12v+13+37\\\\-2v=-12v+50\qquad\text{add}\ 12v\ \text{to both sides}\\\\-2v+12v=50\\\\(-2+12)v=50\\\\10v=50\qquad\text{divide both sides by 10}\\\\(10v)/(10)=(50)/(10)\\\\v=5`

Answer 2

v = 5

Explanation:

-37 -2v = -6 (2v - 3) - 5

-2v - 37 = -6 (6*2v - 6*3) - 5

-2v - 37 = - (12v - 18) - 5 combine like terms

-37 - 18 + 5 = -12v + 2v

-50 = -10v

v = -50 / -10

v = 5

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