Question

Solve the Equation. 20x + 12 ≥ 14x + 30 A. x ≥ 7 B. x ≤ 7 C. x ≥ 3 D. x ≤ 3

Answer 1

`\huge\boxed{C.\ x\geq3}`

Explanation:

`20x+12\geq14x+30\qquad\text{subtract 12 from both sides}\\\\20x+12-12\geq14x+30-12\\\\20x\geq14x+18\qquad\text{subtract}\ 14x\ \text{from both sides}\\\\20x-14x\geq14x-14x+18\\\\6x\geq18\qquad\text{divide both sides by 6}\\\\(6x)/(6)\geq(18)/(6)\\\\\boxed{x\geq3}`

Answer 2

x≥3

Explanation:

Treat the ≥ symbol like it is an equals sign. First, subtract 14x from each side to get 6x+12≥30. Then, Subtract 12 from each side to get 6x≥18. I will let you solve the rest :)