Answer:
Hence a = -1, b = 10
Explanation:
Given h(x) = (x - 1)³ + 10, f(x) = x + a and g(x) = x³ + b so that h(x) = (gof)(x)
To get the value of a and b that will make the composite function true, we will first need to get the composite function (gof)(x).
(gof)(x) = g[f(x)]
g[f(x)] = g[ x + a]
To get g(x+a), we will replace the variable x in the function g(x) = x+b with x+a as shown;
g[x + a] = (x+a)³+b
Hence (gof)(x) = (x+a)+b
Equating h(x) = (gof)(x)
(x - 1)³ + 10 = (x+a)³+b
On comparing both sides of the equation;
(x - 1)³ = (x+a)³ and 10 = b
For (x - 1)³ = (x+a)³
Take cube root of both sides
∛ (x - 1)³ = ∛(x+a)³
x-1 = x+a
collect like terms
a = x-x-1
a = -1
Hence a = -1, b = 10