Question

Water flows through a valve with inlet and outlet velocities of 3 m/s. If the loss coefficient of the valve is 2.0, and the specific weight of water is 9800 N/m3, the pressure drop across the valve is most nearly:

Answer 1

The value is
`\delta P = 9000 \ Pa`

Step-by-step explanation:

From the question we are told that

The inlet and outlet velocity is
`v = 3 \ m/s`

The loss coefficient is
`k = 2`

Th specific weight of water is
`w = 9800 \ N/m^3`

Generally the pressure drop across the valve is mathematically represented as

`\delta P = (1)/(2) * k * \rho * v^2`

Here
`\rho` is the density which is mathematically represented as

`\rho = (w)/(g)`

=>
`\rho = (9800)/(9.8)`

=>
`\rho = 1000 \ kg/m^3`

So

`\delta P = (1)/(2) * 2* 1000 * 3^2`

`\delta P = 9000 \ Pa`