Answer:
The number of times Ivan and Adeline have the same number written on the board is 6.
Explanation:
Consider the procedure as follows:
- On each half of the board, the number 2 is written.
- On Ivan's teacher's signal, Ivan multiplies the number on his side of the board by -2 and writes the answer on the board, erasing the number he started with.
- Adeline does the same on each signal, except that she multiplies by 2.
- The teacher gives 10 signals in total.
Consider the numbers on each half of the board:
Ivan Adeline
2 2
2 × -2 = -4 2 × 2 = 4
-4 × -2 = 8 4 × 2 = 8
8 × -2 = -16 8 × 2 = 16
-16 × -2 = 32 16 × 2 = 32
32 × -2 = -64 32 × 2 = 64
-64 × -2 = 128 64 × 2 = 128
128 × -2 = -256 128 × 2 = 256
-256 × -2 = 512 256 × 2 = 512
512 × -2 = -1024 512 × 2 = 1024
-1024 × -2 = 2048 1024 × 2 = 2048
Thus, the number of times Ivan and Adeline have the same number written on the board is 6.