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Solve by completing the square: 5x^2 + 20x +32 = 0 (please show work step by step)

1 Answer

1 vote

5[x²+(2)²—(2)²]+32

5[(x+2)²—4]+32

5(x+2)²—20+32

5(x+2)²+12

Ans

User YvesgereY
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