Question

You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced 7.5 x 103 meters apart. However, by placing a piece of crystal in one of the slits, you are able to make it so that the rays of light that travel through the two slits are Ï out of phase with each other (that is to say, Ao,- ). If you observe that on a screen placed 4 meters from the two slits that the distance between the bright spot clos center of the pattern is 1.5 cm, what is the wavelength of the laser?

Answer 1

Complete Question

You are performing a double slit experiment very similar to the one from DL by shining a laser on two nattow slits spaced
`7.5 * 10^(-3)` meters apart. However, by placing a piece of crystal in one of the slits, you are able to make it so that the rays of light that travel through the two slits are Ï out of phase with each other (that is to say, Ao,- ). If you observe that on a screen placed 4 meters from the two slits that the distance between the bright spot closest to center of the pattern is 1.5 cm, what is the wavelength of the laser?

Answer:

The wavelength is
`\lambda = 56250 nm`

Step-by-step explanation:

From the question we are told that

The distance of slit separation is
`d = 7.5 *10^(-3) \ m`

The distance of the screen is
`D = 4 \ m`

The distance between the bright spot closest to the center of the interference is
`k = 1.5 \ cm = 0.015 \ m`

Generally the width of the central maximum fringe produced is mathematically represented as

`y = 2 * k = ( D * \lambda)/(d)`

=>
`2 * 0.015 = ( \lambda * 4)/( 7.5 *10^(-3))`

=>
`\lambda = 56250 *10^(-9) \ m`

=>
`\lambda = 56250 nm`