Question

Find the first three terms of this sequence tn=4n²+2

Answer 1

Explanation:

finding the first term by putting n=1

t(1)=4.
`(1)^(2)` +2 = 4.1 +2 = 4+2 = 6

finding the second term by putting n=2

t(2)=4.
`(2)^(2)` +2 = 4.4 +2 = 16+2 = 18

finding the third term by putting n=3

t(3)=4.
`(3)^(2)` +2 = 4.9 +2 = 36+2 = 38

hence first three terms are:

6,18,38,......,4
`n^(2)` +2