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Given that :-

  • x+y < 5

  • 3 < x < 5

To Find :-

  • Value of y

Solution :-

The fist expression x + y < 5 states that sum of x and y could be any rational number less than 5 .

And the second expression 3 < x < 5 states that value of x could be any rational number between 3 and 5.

Let's check which option suits best.

Is it possible to have value of 8/3 by y ?

→ x + 8/3 < 5

→ x < 5 - 8/3

x = 7/3

7/3 is a rational number . So y as 8/3 is possible value.

7/3 = 2.33

But value of x should be greater than 3 .

So option A is wrong.

Is it possible to have value 2 by y ?

→ x +2 < 5

→ x < 5-2

→ x < 3 .

But value of X should be greater than 3.

So option B is also incorrect.

Is it possible to have value 0 by y?

→ x +0 <5

→ x < 5

It also fullfill 2nd expression that X should have value less than 5 and greater than 3.

So option C is valid .

Value of y is 0 .

User Bernatfortet
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