Given that :-
To Find :-
Solution :-
The fist expression x + y < 5 states that sum of x and y could be any rational number less than 5 .
And the second expression 3 < x < 5 states that value of x could be any rational number between 3 and 5.
Let's check which option suits best.
Is it possible to have value of 8/3 by y ?
→ x + 8/3 < 5
→ x < 5 - 8/3
→ x = 7/3
7/3 is a rational number . So y as 8/3 is possible value.
→ 7/3 = 2.33
But value of x should be greater than 3 .
So option A is wrong.
Is it possible to have value 2 by y ?
→ x +2 < 5
→ x < 5-2
→ x < 3 .
But value of X should be greater than 3.
So option B is also incorrect.
Is it possible to have value 0 by y?
→ x +0 <5
→ x < 5
It also fullfill 2nd expression that X should have value less than 5 and greater than 3.
So option C is valid .
Value of y is 0 .