Answer:
x = 1, y = -1 so C)
Explanation:
Solve the following system:
{5 y + 3 x = -2 | (equation 1)
-y + 2 x = 3 | (equation 2)
Subtract 2/3 × (equation 1) from equation 2:
{3 x + 5 y = -2 | (equation 1)
0 x - (13 y)/3 = 13/3 | (equation 2)
Multiply equation 2 by 3/13:
{3 x + 5 y = -2 | (equation 1)
0 x - y = 1 | (equation 2)
Multiply equation 2 by -1:
{3 x + 5 y = -2 | (equation 1)
0 x + y = -1 | (equation 2)
Subtract 5 × (equation 2) from equation 1:
{3 x + 0 y = 3 | (equation 1)
0 x + y = -1 | (equation 2)
Divide equation 1 by 3:
{x + 0 y = 1 | (equation 1)
0 x + y = -1 | (equation 2)
Collect results:
Answer: {x = 1, y = -1