Answer:
$416.67
Explanation:
The problem statement gives us a range of values that Keith might use from his birthday gift. It asks for the maximum monthly amount that Keith would need to save.
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savings
If x is the amount Keith must save monthly, then his savings in two years will be 2(12x) = 24x. Added to the 3000 he has already saved, the amount he must spend from his birthday gift will be the difference between the car price and his savings:
15000 -(3000 +24x) = 12000 -24x
birthday gift
We are told this will be at least 2000, but it can be no more than 2500 (the amount of the gift), so we have ...
2000 ≤ 12000 -24x ≤ 2500
monthly amount
Solving this, we find ...
-10000 ≤ -24x ≤ -9500 . . . . . . subtract 12000
416.67 ≥ x ≥ 395.83 . . . . . . . . divide by -24 (reverses the inequality)
The most Keith would have to save each month is $416.67.
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Additional comment
The 2500 amount does not actually come into play when computing the maximum he must save each month. It sets the minimum Keith must save.