Hello,
4. you have sequences defined by the first term and a recursive relation.

Take n = 2, it gives
, right?
But you know

so

This is the second term. You are asked to find the first three terms.
Now, let's take n = 3

So the first three terms are 3, 6, 12.
6.

8.

10.

Do not hesitate if you have any question.
Thank you