Question

Write the Ksp expression for the sparingly soluble compound chromium(III) hydroxide, Cr(OH)3.

Ksp =________

Answer 1

Answer and Explanation: Ksp is the Solubility Product Constant and is the equilibrium constant that happens when a solid is dissolved in an aqueous solution.

The dissolution of chromium (III) hydroxide:

`Cr(OH)_(3)_((s))` ⇄
`Cr^(3+)_((aq)) + 3OH^(-)_((aq0))`

Every equilibrium constant is of the form:

`K = ([products]^(coefficient))/([reagents]^(coefficient))`

Then,

`K_(sp) = [Cr^(3+)_((aq))][OH^(-)_(aq)]^(3)`

The reagent is not included because solids don't take part in euqilibrium constants.

So, Ksp of chromium (III) hydroxide is
`K_(sp) = [Cr^(3+)_((aq))][OH^(-)_(aq)]^(3)`