Answer :
(a). The speed of the block is 0.395 m/s.
(b). No
Explanation :
Given that,
Diameter = 20.0 cm
Power = 26.0 MW
Mass = 110 kg
diameter = 20.0 cm
Distance = 100 m
We need to calculate the pressure due to laser
Using formula of pressure
![P_(r)=(I)/(c)](https://img.qammunity.org/2021/formulas/physics/college/9alku9l2140xqzx3iwpkmx0tj9b5oslk2s.png)
![P_(r)=(P)/(Ac)</p><p>Put the value into the formula</p><p>[tex]P_(r)=(26.0*10^(6))/(\pi*(10*10^(-2))^2*3*10^(8))](https://img.qammunity.org/2021/formulas/physics/college/k4ksf1wqf21iypbg9ajjyctdhs2rrusnja.png)
![P_(r)=2.75\ N/m^2](https://img.qammunity.org/2021/formulas/physics/college/uqm2ebpuckmmgq2qzx3eeegk8ivq0tvonq.png)
We need to calculate the force
Using formula of force
![F=P* A](https://img.qammunity.org/2021/formulas/physics/high-school/3s7yf8hqoyvbe70zpojl0k6llnmr2mxmj5.png)
![F=P* \pi r^2](https://img.qammunity.org/2021/formulas/physics/college/2y93x3joem7pyzjglyh5iw2fhmf11os7qa.png)
Put the value into the formula
![F=2.75*\pi (0.01)^2](https://img.qammunity.org/2021/formulas/physics/college/sx4nmmyiq2h9f2ujexg88clqwvx56o288c.png)
![F=0.086\ N](https://img.qammunity.org/2021/formulas/physics/college/39ye9qzsgexapzuuqle5687s3n2huvk9ta.png)
We need to calculate the acceleration
Using formula of force
![F=ma](https://img.qammunity.org/2021/formulas/physics/college/kxqi3lxi3fjfv761qhdu0s1p00agxd9vve.png)
Put the value into the formula
![0.086=110* a](https://img.qammunity.org/2021/formulas/physics/college/zilnjmrimu510iikvsbxgy1dl49i6i0mcz.png)
![a=(0.086)/(110)](https://img.qammunity.org/2021/formulas/physics/college/b9qwrpgvzvfclzi3ip8wkif124jfcp3le6.png)
![a=0.000781\ m/s^2](https://img.qammunity.org/2021/formulas/physics/college/kgrxg3a5qu6rkw9m48jzmdskaadsz5t5u3.png)
![a=7.81*10^(-4)\ m/s^2](https://img.qammunity.org/2021/formulas/physics/college/q6mama6j5s5lgd6kv68cu90d2w1x1e7w1m.png)
(a). We need to calculate speed of the block
Using equation of motion
![v^2=u^2+2ad](https://img.qammunity.org/2021/formulas/physics/college/kihy1xcwd9na76ppwbghpuq168zt5k3wm2.png)
Put the value into the formula
![v=\sqrt{2*7.81*10^(-4)*100}](https://img.qammunity.org/2021/formulas/physics/college/gt1gcnqhu9ylhl1wyraxnwmp0s67qvm04k.png)
![v=0.395\ m/s](https://img.qammunity.org/2021/formulas/physics/college/8hfhpsim5wu6kvol3np6r1val03u6v138d.png)
(b). No because the velocity is very less.
Hence, (a). The speed of the block is 0.395 m/s.
(b). No