Answer:
A) for 100 : < 1 times
b) for 750 : < 1 times
c) For 2000 = 1 time
D) for 10000 = 4 times
E) for 100000 = 7 times
Step-by-step explanation:
Given data:
load factor = 75%
initial capacity = 1000
The number of times the enlarge method will be called for a unique number of entries would be 2 times the initial capacity ( 1000 ) because the load factor = 75% = 0.75
A) for 100 : < 1 times
b) for 750 : < 1 times
C) For 2000
= initial capacity * 2 = 2000 ( 1 time )
D) for 10000
= 1000 * 2 *2 *2*2 = 16000 ( 4 times )
to make it 10000 we have to add another 2000 which will make the number of times = 4 times
E)for 100000
= 1000*2*2*2*2*2*2*2= 128000 ( 7 times )
unique entry of 100000 is contained in 7 times