Question

Write the equation of the line in slope intercept form that passes through (10,21) and (15,36)

Answer 1

y = 3x - 9

Explanation:

First, find the slope using rise/run (y2 - y1) / (x2 - x1)

Plug in the points:

(36 - 21) / (15 - 10)

15/5

= 3

Next, plug the slope and a point into the equation y = mx + b to find b (y-int)

y = mx + b

21 = 3(10) + b

21 = 30 + b

-9 = b

Then, plug this into the equation, as well as the slope:

y = 3x - 9