Question

Use the quadratic formula to solve. Round to the nearest tenth if necessary.
2x^2 -3x -7 = 0

Answer 1

The quadratic formula is:

`(-b + √(b^2 - 4ac) )/(2a)` and
`(-b - √(b^2 - 4ac) )/(2a)`

In this case, a = 2, b = -3, and c = -7

So, we can plug in the numbers to get:

`(-(-3) + √((-3)^2 - 4(2)(-7)) )/(2(2))` and
`(-(-3) - √((-3)^2 - 4(2)(-7)) )/(2(2))`

Simplifying, we get:

`(3 + √(65) )/(4)` and
`(3 - √(65) )/(4)`

You need to use a calculator to find what these would be in decimal form. The answer, rounded to the nearest tenth, is: x = 2.8, x = -1.3