Answer:
B. R is NP Hard
Step-by-step explanation:
Given:
S is an NP complete problem
Q is not known to be in NP
R is not known to be in NP
Q is polynomial times reducible to S
S is polynomial times reducible to R
Solution:
NP complete problem has to be in both NP and NP-hard. A problem is NP hard if all problems in NP are polynomial time reducible to it.
Option B is correct because as given in the question S is an NP complete problem and S is polynomial times reducible to R.
Option A is not correct because R is not known to be in NP
Option C is not correct because Q is also not known to be in NP
Option D is not correct because Q because no NP-complete problem is polynomial time reducible to Q.