Question

A 19.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.8-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.22 s .

Required:
What is the average induced emf in the loop?

Answer 1

Given that,

Diameter of the loop, d = 19.5 cm

Magnetic field, B = 1.8 T

The loop is rotated so that its plane is parallel to the field direction in 0.22 s. We need to find the average induced emf in the loop.

When it is placed perpendicular to the magnetic field, angle between Area vector and Magnetic Field will be 0. Flus is BA.

When it is rotated so that its plane is parallel to the field direction, angle between Area vector and Magnetic Field will be 90. Flus is 0.

The induced emf is given by :

`\epsilon=(-d\phi)/(dt)\\\\\epsilon=(BA)/(t)\\\\\epsilon=(1.8* \pi * (19.5/2)^2)/(0.22)\\\\\epsilon=2443.48\ V`

So, the average induced emf in the loop is 2443.48 volts.