Question

A box contains 12 balls: 8 red and 4 black. Two extractions are made without replacing the extracted ball to the box before the second extraction. Do you find the probability of drawing a ball of each color?

Answer 1

16/33

Explanation:

The probability that the first ball is red and the second ball is black is:

8/12 × 4/11 = 8/33

The probability that the first ball is black and the second ball is red is:

4/12 × 8/11 = 8/33

So the total probability of drawing one ball of each color is 8/33 + 8/33 = 16/33.