Answer:
Nitrogen 13
Step-by-step explanation:
We need fill in the blank the nuclide symbol for the missing particle in the following nuclear equation.
![X\rightarrow ^0e_1+^(13)C_6](https://img.qammunity.org/2021/formulas/physics/college/xrtcteyx1g5jcac6dv84jpb87t6gbwh3yj.png)
In this reaction, the emission of positron takes place. The atomic number in the LHS and the RHS should be same. So,
![^(13)_7 N \rightarrow ^0e_1+^(13)C_6](https://img.qammunity.org/2021/formulas/physics/college/bu764o7hao1c7w6csof0nn7x85ca4tubbe.png)
So, the LHS have nitrogen 13, a radioactive isotope.