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Fill in the nuclide symbol for the missing particle in the following nuclear equation.

_______ → + 0 e1 + 13C6

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Answer:

Nitrogen 13

Step-by-step explanation:

We need fill in the blank the nuclide symbol for the missing particle in the following nuclear equation.


X\rightarrow ^0e_1+^(13)C_6

In this reaction, the emission of positron takes place. The atomic number in the LHS and the RHS should be same. So,


^(13)_7 N \rightarrow ^0e_1+^(13)C_6

So, the LHS have nitrogen 13, a radioactive isotope.

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