Question

A 18-kg hammer strikes a nail at a velocity of 7.6 m/s and comes to rest in a time interval of 8.3 ms .

Required:
a. What is the impulse given to the nail?
b. What is the average force acting on the nail?

Answer 1

The impulse given to the nail is [impulse value], and the average force acting on the nail is [average force value].

Step-by-step explanation:

a. To find the impulse given to the nail, we can use the formula:

Impulse = Change in momentum

Momentum = mass x velocity

Initial momentum = 18 kg * 7.6 m/s

Final momentum = 0 kg * 0 m/s (rest)

Change in momentum = Final momentum - Initial momentum

Impulse = Change in momentum = 0 kg * 0 m/s - 18 kg * 7.6 m/s

Therefore, the impulse given to the nail is 0 kg * 0 m/s - 18 kg * 7.6 m/s.

b. To find the average force acting on the nail, we can use the formula:

Average force = Impulse / Time interval

Average force = (0 kg * 0 m/s - 18 kg * 7.6 m/s) / (8.3 ms)

Therefore, the average force acting on the nail is (0 kg * 0 m/s - 18 kg * 7.6 m/s) / (8.3 ms).