Question

Two parallel very long straight wires carrying current of 5A each are kept at a separation of 1m. If the currents are in the same direction, the force per unit length between them is __________

Answer 1

The force per unit between the two parallel wires with same current flowing in the same direction is 5 x 10⁻⁶ N/m repulsive force.

Step-by-step explanation:

Given;

current though the two parallel wires, I₁ and I₂ = 5A

distance between the two wires, R = 1 m

The force per unit of the wires is calculated as;

`(F)/(L) = (\mu_o I_1I_2)/(2\pi R)`

Where;

μ₀ is permeability of free space = 4π x 10⁻⁷ m/A

Substitute in the given values into the equation and determine the force per unit length (F/L).

`(F)/(L) = (\mu_o I_1I_2)/(2\pi R) \\\\ (F)/(L) = (4\pi *10^(-7)*5*5)/(2\pi *1)\\\\ (F)/(L) = 5*10^(-6) \ N/m \ (repulsive)`

Therefore , the force per unit between the two parallel wires with same current flowing in the same direction is 5 x 10⁻⁶ N/m repulsive force.