Question

If the magnetic field is held constant at 3.0 T and the loop is pulled out of the region that contains the field in 0.2 s, what is the magnitude of the average induced emf in the loop

Answer 1

emf = 15 * Area and if A is given in square meters, the units of the emf will be Volts

Step-by-step explanation:

Assuming that the area of the loop of current (A) is known, the magnitude of the induced emf can be calculated using Faraday-Lenz's Law:

`emf=|-(\Delta\,\Phi)/(\Delta \,t) |=|(A\,B)/(\Delta \,t)|=|(A\,(3))/(0.2)|=15\,A`

and if the area (A) is given in square meters, the emf will directly come in units of Volts.