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For each of the following vector fields

F, decide whether it is conservative or not by computing the appropriate first order partial derivatives. Type in a potentialfunction f (that is, ∇f = F) with f(0,0)=0. If it is not conservative, type N.
A. F(x,y)=(−16x+2y)i+(2x+10y) j f(x,y)= _____
B. F(x,y)=−8yi−7xj f(x,y)=_____
C. F(x,y)=(−8sin y)i+(4y−8xcosy)j f(x,y)=_____

1 Answer

2 votes

(A)


(\partial f)/(\partial x)=-16x+2y


\implies f(x,y)=-8x^2+2xy+g(y)


\implies(\partial f)/(\partial y)=2x+(\mathrm dg)/(\mathrm dy)=2x+10y


\implies(\mathrm dg)/(\mathrm dy)=10y


\implies g(y)=5y^2+C


\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}

(B)


(\partial f)/(\partial x)=-8y


\implies f(x,y)=-8xy+g(y)


\implies(\partial f)/(\partial y)=-8x+(\mathrm dg)/(\mathrm dy)=-7x


\implies (\mathrm dg)/(\mathrm dy)=x

But we assume
g(y) is a function of
y alone, so there is not potential function here.

(C)


(\partial f)/(\partial x)=-8\sin y


\implies f(x,y)=-8x\sin y+g(x,y)


\implies(\partial f)/(\partial y)=-8x\cos y+(\mathrm dg)/(\mathrm dy)=4y-8x\cos y


\implies(\mathrm dg)/(\mathrm dy)=4y


\implies g(y)=2y^2+C


\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}

For (A) and (C), we have
f(0,0)=0, which makes
C=0 for both.

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