Answer:
B) approaches infinity
Step-by-step explanation:
The capacitive reactance of an AC capacitor is given by;
![X_C = (1)/(\omega C ) = (1)/(2\pi f C)](https://img.qammunity.org/2021/formulas/physics/college/xhx8hfi5k9nzkfxc8ui8sdx5m1q7ex3i1s.png)
Where;
C is the capacitance
f is the frequency of the ac voltage
![X_C = (1)/(\omega C) = (1)/(2\pi f C) \\\\X_C = (1)/(2\pi f C) \\\\X_C = (1)/(2\pi (0) C) \\\\X_C = (1)/(0) \\\\X_C = \ infinity](https://img.qammunity.org/2021/formulas/physics/college/1xea1i0tveyrwc0moc1ejm9c8zvcp11rom.png)
Therefore, as the frequency of the ac voltage across a capacitor approaches zero, the capacitive reactance of that capacitor approaches infinity.
The correct option is (B) approaches infinity