Question

A parallel plate capacitor consists of two square parallel plates separated by a distance d. the potential across the plates, while keeping everything else constant, what happens to the energy stored in the capacitor?

A) There will be % of the energy stored
B) There will be % of the energy stored
C) The energy stored will remain constant
D) The energy stored will double
E) the energy stored will quadruple

Answer 1

E) the energy stored will quadrupled

Step-by-step explanation:

The correct question is

A parallel plate capacitor consists of two square parallel plates separated by a distance d. If i double the potential across the plates, while keeping everything else constant, what happens to the energy stored in the capacitor?

A) There will be 1/4 of the energy stored

B) There will be 1/2 of the energy stored

C) The energy stored will remain constant

D) The energy stored will double

E) the energy stored will quadruple

The initial energy stored in the capacitor
`E_(i)` =
`(1)/(2)CV^(2)`

where C is the capacitance

V is the potential difference

If I double this voltage, while holding every other parameters constant, the new energy stored will be

`E_(n)` =
`(1)/(2)C(2V)^(2)` =
`(4)/(2)CV^(2)`

`E_(n)` =
`2CV^(2)`

dividing new energy stored by the initial energy stored, we have

`E_(n)/E_(i)` =
`2CV^(2)` ÷
`(1)/(2)CV^(2)` = 4

the energy stored will be quadrupled.