Question

A voltmeter and an ammeter are used to respectively monitor the voltage across and the current through a resistor connected to an AC source. If the resistor has a value of 11.5 Ω and the ammeter reads 7.24 A, determine the following.

(a) the rms voltage (in V) across the resistor
(b) the peak voltage (in V) of the source
(c) the maximum current (in A) in the resistor
(d) the average power (in W) delivered to the resistor

Answer 1

a) 85.1 V

b)120.4 V

c) 10.24 A

d) 602.8 W

Step-by-step explanation:

The reading of the ammeter is the root mean square value of current.

a) Vrms= Irms R

Irms= 7.24 A

R= 11.5 Ω

Vrms= 7.4A × 11.5Ω

Vrms= 85.1 V

b)

Peak value of voltage (Vo)= Vrms/0.707

Vo=85.1/0.707

Vo=120.4 V

c)

Peak current= Irms/0.707

Io= 7.24/0.707

Io= 10.24 A

d) average power= Irms^2 × R

Power= (7.24)^2 ×11.5

Power= 602.8 W