Answer:
The depth of water at the point is
![d_A = 6.55 \ m](https://img.qammunity.org/2021/formulas/physics/college/os8b5qb8oz4y4c6vakin5z9vxueeujarxq.png)
Step-by-step explanation:
From the question we are told that
The height of the person above water is
![d = 3.00 \ m](https://img.qammunity.org/2021/formulas/physics/college/lxltlc6bc11yb90ruzh276yyi6nmgovj6i.png)
The distance of the coin as seen by the person is
![d' = 8.00 \ m](https://img.qammunity.org/2021/formulas/physics/college/ae7nfrt9hys3fhol8hwld9cd3oojvdk4hl.png)
Generally the apparent depth is mathematically represented as
![d_a = (d_A)/(n)](https://img.qammunity.org/2021/formulas/physics/college/big81l3nqmmal6gow5dr5dbz7sqnxgsf9r.png)
Here
is the actual depth of water while n is the refractive index of water with a constant value
![n = 1.33](https://img.qammunity.org/2021/formulas/physics/college/rgtrjsfe5h1vmr7hc84ee69nhuijctm5qo.png)
Now from the point the person is the apparent depth is evaluated as
![d_a = d'-d](https://img.qammunity.org/2021/formulas/physics/college/y6pnjtlobanb912k9t2zgpa3k2ujfb6qxg.png)
=>
![d_a = 8 - 3](https://img.qammunity.org/2021/formulas/physics/college/qn0v5fn2acths1j58dzkommod35hmmghrp.png)
=>
![d_a = 5 \ m](https://img.qammunity.org/2021/formulas/physics/college/zsz2ietkxzql5qcg04b8inbs1a98ckcabo.png)
So
![5 = (d_A)/(1.33)](https://img.qammunity.org/2021/formulas/physics/college/s2as06f72gc15xra8fz4fwq1df3kru81ik.png)
=>
![d_A = 5 * 1.33](https://img.qammunity.org/2021/formulas/physics/college/lmno5ioubvrfjgpg28ivrq6cvvro5gfdac.png)
=>
![d_A = 6.55 \ m](https://img.qammunity.org/2021/formulas/physics/college/os8b5qb8oz4y4c6vakin5z9vxueeujarxq.png)