Question

The claim is that for a smartphone​ carrier's data speeds at​airports, the mean= 14.00Mbps. The sample size is equals=27 and the test statistic is t equals=1.386.

What is the P-value=

Answer 1

Degree of freedom = sample size -1 = 27-1 = 26

Given t = 1.386

This is a two tailed test.

Using a TI83/84 calculator:

2 x tcdf(1e99,-1.386,26) = 0.177520

The p value = 0.177520 (round the answer as needed)