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Pls solve no;3a,b,c the picture will be
given thank u​
use trigonometry u solve it

Pls solve no;3a,b,c the picture will be given thank u​ use trigonometry u solve it-example-1
User Brewmanz
by
8.6k points

1 Answer

1 vote

Answer/Step-by-step explanation:

3.a. length of AC.

Hypotenuse = AC

Opposite side to 60° = 7

Therefore,
sin(60) = (7)/(AC)


AC*sin(60) = (7)/(AC)*AC


AC*sin(60) = 7


AC = (7)/(sin(60))


AC = 8.1 (to nearest tenth)

b. Length of BC

Hypotenuse = BC

Opposite side to 50° = 7

Therefore,
sin(50) = (7)/(BC)


BC*sin(50) = (7)/(BC)*AC


BC*sin(50) = 7


BC = (7)/(sin(50))


BC = 9.1 (to nearest tenth)

c. Length of AB

Use the law of sines to find AB


(BC)/(sin(A)) = (AB)/(sin(C)}

m<C = 180 - (60 + 50) (sum of angles in a triangle) = 70°

m<A = 60°

BC = 9.1

AB = ?


(9.1)/(sin(60)) = (AB)/(sin(70))

Cross multiply


9.1*sin(70) = AB*sin(60)

Divide both sides by sin(60)


(9.1*sin(70))/(sin(60)) = (AB*sin(60))/(sin(60))


(9.1*sin(70))/(sin(60)) = AB


9.9 = AB (nearest tenth)


AB = 9.9

User Alkersan
by
7.8k points

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