Question

Pls solve no;3a,b,c the picture will be
given thank u​
use trigonometry u solve it

Answer 1

Answer/Step-by-step explanation:

3.a. length of AC.

Hypotenuse = AC

Opposite side to 60° = 7

Therefore,
`sin(60) = (7)/(AC)`

`AC*sin(60) = (7)/(AC)*AC`

`AC*sin(60) = 7`

`AC = (7)/(sin(60))`

`AC = 8.1` (to nearest tenth)

b. Length of BC

Hypotenuse = BC

Opposite side to 50° = 7

Therefore,
`sin(50) = (7)/(BC)`

`BC*sin(50) = (7)/(BC)*AC`

`BC*sin(50) = 7`

`BC = (7)/(sin(50))`

`BC = 9.1` (to nearest tenth)

c. Length of AB

Use the law of sines to find AB

`(BC)/(sin(A)) = (AB)/(sin(C)}`

m<C = 180 - (60 + 50) (sum of angles in a triangle) = 70°

m<A = 60°

BC = 9.1

AB = ?

`(9.1)/(sin(60)) = (AB)/(sin(70))`

Cross multiply

`9.1*sin(70) = AB*sin(60)`

Divide both sides by sin(60)

`(9.1*sin(70))/(sin(60)) = (AB*sin(60))/(sin(60))`

`(9.1*sin(70))/(sin(60)) = AB`

`9.9 = AB` (nearest tenth)

`AB = 9.9`