Question

Root 3 + root 2 /root 3- root 2 = a+b root 6 ​

Answer 1

5 + 2
`√(6)`

Explanation:

Given

`(√(3)+√(2) )/(√(3)-√(2) )`

Multiply numerator/ denominator by the conjugate of the denominator

The conjugate of
`√(3)` -
`√(2)` is
`√(3)` +
`√(2)`

=
`((√(3)+√(2))(√(3)+√(2)) )/((√(3)-√(2))(√(3)+√(2)) )` ← expand numerator/ denominator using FOIL

=
`(3+√(6) +√(6)+2 )/(3-2)`

=
`(5+2√(6) )/(1)`

= 5 + 2
`√(6)` → with a = 5 and b = 2