Question

If a=mg-kv2/m,find,correct to the nearest whole number the value of v when a=2.8,m=12,g=9.8 and k=8/3

Answer 1

The value of
`v` is ± 22.729.

Explanation:

Let be
`a=m\cdot g -(k\cdot v^(2))/(m)`, the variable
`v` is now cleared:

`(k\cdot v^(2))/(m)=m\cdot g -a`

`k\cdot v^(2) = m^(2)\cdot g- m\cdot a`

`v^(2) = (m^(2)\cdot g - m\cdot a)/(k)`

`v =\pm \sqrt{(m^(2)\cdot g-m\cdot a)/(k) }`

If
`a = 2.8`,
`m=12`,
`g = 9.8` and
`k = (8)/(3)`, the value of
`v` is:

`v=\pm \sqrt{((12)^(2)\cdot (9.8)-(12)\cdot (2.8))/((8)/(3) ) }`

`v \approx \pm 22.729`

The value of
`v` is ± 22.729.