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Consider a rectangle whose length, L, is 4 more than twice its width, w. a. Write an expression for L in terms of w. b. Show that the perimeter, P, is equal to = 6 + 8. c. Given the perimeter is 20, find the length and width of the rectangle using your answer to part b.

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Answer:

Explanation:

a)L=2w+4

b)P=2L+2w

sub L=2w+4,

P=2(2w+4)+2w

P=4w+8+2w

P=6w+8

c) 20=6w+8

12=6w

2=w

L=2(2)+4

=8

Hence,

L=8 and w=2

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