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You have a box with 6 blue marbles, 7 red marbles, and 2 yellow marbles. You are going to pull out one

marble, record its color, put it back in the box and draw another marble. What is the probability of
pulling out a yellow marble followed by a blue marble?

2 Answers

2 votes

Answer as a fraction = 4/75

Answer in decimal form = 0.05333 (approximate)

Answer in percent form = 5.333% (approximate)

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Work Shown:

A = event of pulling a yellow marble on the first selection

P(A) = 2/15 since there are 2 yellow out of 6+7+2=15 total.

B = event of pulling a blue marble on the second selection

P(B) = 6/15 = 2/5

Note how the 15 does not drop to 14 since we put the first marble back. Therefore events A and B are independent

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P(A and B) = probability of getting yellow, then blue

P(A and B) = P(A)*P(B)

P(A and B) = (2/15)*(2/5)

P(A and B) = (2*2)/(15*5)

P(A and B) = 4/75

P(A and B) = 0.05333 approximately

P(A and B) = 5.333% approximately

User Bob Van Luijt
by
4.6k points
4 votes

Answer:

12/225 or 4/75.

Explanation:

I hope this helps!

User Qweruiop
by
5.3k points