Logx+log(3x-5)=log2

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Logx+log(3x-5)=log2

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Jerome solved the equation below by graphing. log_2x+log_2(x-2)=3 Which of the following shows the correct system of equations and solution? a.) y_1=logx/log2 +log(x-2)/log2 y_2=3, x=3 b.) y_1=logx/log2

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HELP!! Solve for x: logx - log(x+5) = log2 need step-by-step solution

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Logx+log(3x-5)=log2

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Logx+log(3x-5)=log2