Answer:
The present age of the woman is 37 years and her daughter is 7 years
Explanation:
two years ago a woman was 7 times old as her daughter, but in 3 years time she would be 4 times old as the girl. how old are they now
Two years ago a woman wad 7 times as old as her daughter
Let her daughter=x-2
The woman=y-2
x-2
7(y-2)=7y-14
x-2=7y-14
x-7y=-14+2
x-7y= -12 (1)
but in 3 years time she would be 4 times as old as the girl.
x+3
y+3
x+3
4(y+3)=4y+12
x+3=4y+12
x-4y=12-3
x-4y=9. (2)
x-7y= -12 (1)
x-4y=9. (2)
Subtract (1) from (2)
4y-(-7y)=9-(-12)
-4y+7y=9+12
3y=21
y=21/3
y=7
Substitute
y=7 into (1)
x-7y= -12
x-7(7)=-12
x-49=-12
x= -12+49
=37
The present age of the woman is 37 years and her daughter is 7 years