Register

Logx - logx-1^2=2log(x-1) what is the value of x​

Logx - logx-1^2=2log(x-1) what is the value of x​
86.0k views
1 vote
Logx - logx-1^2=2log(x-1) what is the value of x​

User Asinkxcoswt
by
8.1k points

1 Answer

4 votes

Answer:

Explanation:


logx -log(x-1)^2= 2 log(x-1)


logx-2log(x-1) = 2log(x-1)


logx=log(x-1)^4


x=(x-1)^4


x^4-4x^3+6x^2+1=0

solve this equation

User ValRob
by
8.4k points
← Prev Question Next Question →

Related questions

User Candost
asked Nov 6, 2021 128k views
If x²+y²=6xy then prove that 2log(x+y)=logx+logy+3log2​
Candost asked Nov 6, 2021
by Candost
8.9k points
1 answer
0 votes
128k views
User Mark Glorie
asked Mar 9, 2021 222k views
Logx - logx-1^2=2log(x-1)
Mark Glorie asked Mar 9, 2021
by Mark Glorie
8.0k points
2 answers
3 votes
222k views
User Aaplmath
asked Aug 4, 2021 185k views
Intersection point of Y=logx and y=1/2log(x+1)
Aaplmath asked Aug 4, 2021
by Aaplmath
7.8k points
1 answer
0 votes
185k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
How do you estimate of 4 5/8 X 1/3
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Link Copied!