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Logx - logx-1^2=2log(x-1) what is the value of x​
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Logx - logx-1^2=2log(x-1) what is the value of x​

User Asinkxcoswt
by
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1 Answer

4 votes

Answer:

Explanation:


logx -log(x-1)^2= 2 log(x-1)


logx-2log(x-1) = 2log(x-1)


logx=log(x-1)^4


x=(x-1)^4


x^4-4x^3+6x^2+1=0

solve this equation

User ValRob
by
8.4k points
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