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Find t12 for a geometric sequence where t1=2+2i and r=3

1 Answer

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Answer:


T_(12) = 354294 + 354294i

Explanation:

Given

Geometric Sequence (GP)


T_1 = 2 + 2i


r = 3

Required

Determine T₁₂

The nth term of a GP is calculated as thus;


T_n = ar^(n-1)

In this case;


n = 12;
r = 3 and
a = T_1 = 2 + 2i

Substitute these values in the above formula


T_(12) = (2 + 2i) * 3^(12-1)


T_(12) = (2 + 2i) * 3^(11)


T_(12) = (2 + 2i) * 177147

Open the bracket


T_(12) = 177147 * 2 + 177147 * 2i


T_(12) = 354294 + 354294i

Hence, the 12th term of the sequence is
T_(12) = 354294 + 354294i

User Amritesh Anand
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