Question

Given that p=x^2-y^2/x^2+xy

I. Express p in the simplest form
ii. Find the value of p, if x=-4 and y=-6

Answer 1

When x = -4 and y = -6, p = 37.75

Explanation:

Given that p = x² - y²/x² + x·y, we have;

p = (x² × x² -y² + x·y×x²)/x²

p = (x²⁺² - y² + x¹⁺² × y)/x²

p = (x⁴ - y² + x³·y)/x²

Therefore, p in the simplest form is given as follows;

`p = (x^4 - y^2 + x^3 \cdot y )/(x^2)`

To find the value of p when x = -4 and y = -6, we plug in the value of x and y into the above equation to get the following equation;

`p = ((-4)^4 - (-6)^2 + (-4)^3 \cdot (-6) )/((-4)^2) = 37.75`

Therefore, the value of p when x = -4 and y = -6 is equal to 37.75.