Explanation:
Hey, there!!
As per your question,
There is a Right angled triangle, whose hypotenuse is 13 cm, one side is (13-1)=12 cm.
another side = ?
Let ABC be a Right angled triangle, taking angle "theta" as a refrence angle.
Hypotenuse (h)= 13 cm.
base ( b) = x
perpendicular (p)= 12cm.
By Pythagoras relation we get,



Therefore, base is 5 cm. Or the third side is 5 cm.
Hope it helps...