Answer:
![\boxed{ \boxed{ \boxed{ \bold{ \sf{e = 2}}}}}](https://img.qammunity.org/2021/formulas/mathematics/college/bme18x6ij3kxg7iffdj8abr5gptpul6h0o.png)
Explanation:
![\sf{ (e)/(2) + 7 = 4e}](https://img.qammunity.org/2021/formulas/mathematics/college/vlbv5ps69odce04xuxsm3ik7gcu9oauq27.png)
Take L.C.M of 2 and 1
⇒
![\sf{ (e + 7 * 2)/(2) = 4e}](https://img.qammunity.org/2021/formulas/mathematics/college/61k77aca7kyug6b463jms4xprepriul59m.png)
Multiply the numbers
⇒
![\sf{ (e + 14)/(2) = 4e}](https://img.qammunity.org/2021/formulas/mathematics/college/zjvf002ns2fbut5hr5jhfptbjl421p6liv.png)
Apply cross product property
⇒
![\sf{e + 14 = 8e}](https://img.qammunity.org/2021/formulas/mathematics/college/12jjsoiu8o1zodq66pioxelksaj2mmnxo1.png)
Move variable to left hand side and change it's sign
Similarly, move constant to right hand side and change it's sign
⇒
![\sf{ e - 8e = - 14}](https://img.qammunity.org/2021/formulas/mathematics/college/4axvrcjg7buz4hsowan09i0i7ylzi2np45.png)
Collect like terms
⇒
![\sf{ - 7e = - 14}](https://img.qammunity.org/2021/formulas/mathematics/college/jq8mfrhewawhkpkg5owchlo93sp2qxuuev.png)
Change the signs of both sides of the equation
⇒
![\sf{7e = 14}](https://img.qammunity.org/2021/formulas/mathematics/college/hycqun5wr2gkvh9oz5udle9qbfox4qw7ak.png)
Divide both sides of the equation by 7
⇒
![\sf{ (7e)/(7) = (14)/(7) }](https://img.qammunity.org/2021/formulas/mathematics/college/4ex038tocjbzfgzv5m9veaz9zfp04pcwzt.png)
Calculate
⇒
![\sf{e = 2}](https://img.qammunity.org/2021/formulas/mathematics/college/6bc8pgy0pxtgarh3nv1mw35kybnqbcjwro.png)
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How can we find the L.CM?
The steps for finding L.C.M of the numbers are mentioned below:
Step 1 : First of all find the prime factors of each numbers.
Step 2: Take out the common prime factors. Step 3 : Also take out the other remaining prime factors.
Step 4 : Multiply those all prime factors and obtain L.C.M . If there is not any common prime factors then their L.C.M is the product of the given numbers.
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In our case , we are going to find out the LCM of 2 and 1.
First, Find all prime factors of 2 and 1
2 = 1 × 2
1 = 1 × 1
Common prime factor = 1
Remaining prime factors = 2 and 1
Multiply them : 1 × 2 × 1 = 2
Hope I helped!
Best regards!!