Question

W=-2, x = 3, y=0, z= -1/2 y²-w²/xz​

Answer 1

`=(8)/(3)`

Explanation:

If w = -2, x = 3, y = 2 and z = -1/2 then find the value

`(y^(2)-w^(2) )/(xz)`

Given:

• w = -2
• x = 3
• y = 0
• z = -1/2

Formulas:

• a²-b² = (a+b)(a-b)
• (-a)² = a²
• (-a) × (-b) = ab
• 1/(a/b) = b/a

To find:

`(y^(2)-w^(2) )/(xz)\\`

`(0^(2)-(-2)^(2) )/(3*(-1)/(2) )`

`(0-4)/((-3)/(2) )`

`-4*-(2)/(3)`

`=(8)/(3)`