Question

The winning car in a race beat the second car by 19 ··· 100 of a second. The third car was ·4· 10 of a second behind the second car. By how much did the first car beat the third car?

Answer 1

Add the times together:

19/100 + 4/10

Find the common denominator, which is 100 so rewrite 4/10 as 40/100

Now add:

19/100 + 40/100 = 59/100

The first car beat the third car by 59/100 seconds.