Answer:
y = 3 cos(π/5 x) + 5
Explanation:
The amplitude is half the difference of the min and max.
A = (8 − 2) / 2
A = 3
The midline is the average of the min and max.
C = (8 + 2) / 2
C = 5
The difference in the x values of the min and max is half the period.
T/2 = 5 − 0
T = 10
The function is a maximum at x = 0, so use cosine.
y = 3 cos(2π/10 x) + 5
y = 3 cos(π/5 x) + 5