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Solve for x. A. 24 B. 32 C. 22 D. 35

Solve for x. A. 24 B. 32 C. 22 D. 35-example-1
User DMEM
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1 Answer

6 votes

Answer:

B. 32

Explanation:

The product of the lengths of segments to the near and far circle intercepts are the same, where the length is measured from the point where the secant and tangent meet. The tangent point counts as both circle intercepts, so we have ...

30×30 = 18×(18 +x)

900 = 324 +18x . . . . eliminate parentheses

576 = 18x . . . . . . . . . subtract 324; next, divide by 18

32 = x

User Ralf Ulrich
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